Zero matrix

As the name suggests, a ‘zero’ matrix is just a matrix where all the elements are zero.

Order of a zero matrix

We can have zero matrices of any order (dimensions), for example:

Identity matrix

A zero matrix is the identity matrix for addition. That’s because, if we add a zero matrix to any other matrix of the same order, we get that same matrix back.

For example, if we have the matrix \mathbf{A} = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix} and the zero matrix \mathbf{0} = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}, then:

If you want some algebraic proof:

Multiplication with a zero matrix

If we multiply any matrix by a zero matrix of compatible dimensions, we get a zero matrix as the result.

The proof of this for some 2 \times 2 matrices is as follows:

flashcards

QuestionAnswer
What is a zero matrix?A matrix where all elements are zero.
Can a zero matrix exist in different orders?Yes, they can be of any order (dimensions), e.g. 2 \times 3, 3 \times 2, 4 \times 4, 1 \times 5, 5 \times 1, etc.
For which operation is a zero matrix the identity matrix?It is the identity matrix for matrix addition.
What happens when you add a zero matrix to another matrix of the same order?You get that same matrix back, e.g. \mathbf{A} + \mathbf{0} = \mathbf{A}.
Using algebra, prove \mathbf{A} + \mathbf{0} = \mathbf{A} for a 2 \times 2 matrix.Let \mathbf{A} = \begin{bmatrix} a & b \\ c & d \end{bmatrix} and \mathbf{0} = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}, then \mathbf{A} + \mathbf{0} = \begin{bmatrix} a+0 & b+0 \\ c+0 & d+0 \end{bmatrix} = \begin{bmatrix} a & b \\ c & d \end{bmatrix} = \mathbf{A}.
What happens when you multiply any matrix by a zero matrix of compatible dimensions?You get a zero matrix as the result.
Prove \mathbf{A} \times \mathbf{0} = \mathbf{0} for 2 \times 2 matrices.Let \mathbf{A} = \begin{bmatrix} a & b \\ c & d \end{bmatrix} and \mathbf{0} = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}, then \mathbf{A}\mathbf{0} = \begin{bmatrix} a(0)+b(0) & a(0)+b(0) \\ c(0)+d(0) & c(0)+d(0) \end{bmatrix} = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix} = \mathbf{0}.
How do you prove \mathbf{0} \times \mathbf{A} = \mathbf{0} for 2 \times 2 matrices?Let \mathbf{A} = \begin{bmatrix} a & b \\ c & d \end{bmatrix} and \mathbf{0} = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix}, then \mathbf{0}\mathbf{A} = \begin{bmatrix} 0(a)+0(c) & 0(b)+0(d) \\ 0(a)+0(c) & 0(b)+0(d) \end{bmatrix} = \begin{bmatrix} 0 & 0 \\ 0 & 0 \end{bmatrix} = \mathbf{0}.