Sum of poisson distributions

If X\sim Po(\lambda_X) and Y\sim Po(\lambda_Y), then X+Y\sim Po(\lambda_X + \lambda_Y).

What that means is that, if we have two independent discrete random variables following a poisson distribution, then their sum also follows a poisson distribution, with the mean being the sum of the means of the two original distributions.

Examples

flashcards

QuestionAnswer
If X\sim Po(\lambda_X) and Y\sim Po(\lambda_Y) are independent, what is the distribution of X+Y?X+Y\sim Po(\lambda_X + \lambda_Y)
If X\sim Po(3) and Y\sim Po(5) are independent, what is the distribution of X+Y?X+Y\sim Po(3 + 5) = Po(8)
If X\sim Po(2) and Y\sim Po(4) are independent, what is X+Y?X+Y\sim Po(2 + 4) = Po(6)
If X\sim Po(1) and X+Y\sim Po(2) are independent, what is the distribution of Y?Y\sim Po(2 - 1) = Po(1)
If Y\sim Po(6) and X+Y\sim Po(10) are independent, what is the distribution of X?X\sim Po(10 - 6) = Po(4)
What is the mean of the sum of two independent Poisson distributions?The mean is the sum of the means, i.e., \lambda_X + \lambda_Y