Substitution

Substitution is simply when we relace every instance of a variable in an expression with a value we know.

For example, we may be asked to work out the value of an expression when x= a certain value.

Steps

  1. Replace every instance of the variable in the expression with the given value - put this value inside brackets to avoid mistakes with negative numbers.
  2. Evaluate the expression by just calculating the expression as normal. Make sure to follow the order of operations.

Examples

Find the value of 2x + 3 when x = 4

Find the value of x^2 - 5x + 6 when x = 3

Find the value of 3y^2 + 2y - 4 when y = -2

Find the value of \frac{2a + 5}{a - 1} when a = 6

Find the value of 4b^2 - 3b + 2 when b = \frac{1}{2}

flashcards

QuestionAnswer
What is substitution in algebra?Substitution is when we replace every instance of a variable in an expression with a value we know.
What is the first step in substitution?Replace every instance of the variable in the expression with the given value, putting this value inside brackets to avoid mistakes with negative numbers.
What is the second step in substitution?Evaluate the expression by calculating it as normal, following the order of operations.
Why should you put the given value inside brackets during substitution?To avoid mistakes when dealing with negative numbers.
How do you find the value of 2x + 3 when x = 4?Replace x with (4) to get 2(4) + 3, then evaluate: 2 \times 4 + 3 = 8 + 3 = 11.
How do you find the value of x^2 - 5x + 6 when x = 3?Replace x with (3) to get (3)^2 - 5(3) + 6, then evaluate: 9 - 15 + 6 = -6 + 6 = 0.
How do you find the value of 3y^2 + 2y - 4 when y = -2?Replace y with (-2) to get 3(-2)^2 + 2(-2) - 4, then evaluate: 3 \times 4 + (-4) - 4 = 12 - 4 - 4 = 4.
How do you find the value of \frac{2a + 5}{a - 1} when a = 6?Replace a with (6) to get \frac{2(6) + 5}{(6) - 1}, then evaluate: \frac{12 + 5}{6 - 1} = \frac{17}{5}.
How do you find the value of 4b^2 - 3b + 2 when b = \frac{1}{2}?Replace b with \left(\frac{1}{2}\right) to get 4\left(\frac{1}{2}\right)^2 - 3\left(\frac{1}{2}\right) + 2, then evaluate: 4 \times \frac{1}{4} - \frac{3}{2} + 2 = 1 - \frac{3}{2} + 2 = 3 - \frac{3}{2} = \frac{6}{2} - \frac{3}{2} = \frac{3}{2}.