Stationary wave energy transfer

flashcards

QuestionAnswer
Stationary wave energy transferStationary waves do not transfer energy; they only store it, oscillating between kinetic and potential forms at nodes and antinodes.
Nodes in a stationary wavePoints of zero displacement where the medium is permanently at rest; energy is not transferred past these points.
Antinodes in a stationary wavePoints of maximum displacement where the medium oscillates with greatest amplitude; energy is stored here.
How are stationary waves formed?By the superposition of two identical waves travelling in opposite directions, e.g. incident and reflected waves.
Phase difference between particles in a stationary waveAll particles between two consecutive nodes oscillate in phase; particles on opposite sides of a node oscillate in anti-phase.
Wavelength of a stationary waveTwice the distance between two consecutive nodes (or antinodes): \lambda = 2 \times \text{node spacing}.
Frequency of a stationary waveSame as the frequency of the two travelling waves that produce it.
First harmonic (fundamental) of a string fixed at both endsOne antinode at centre, nodes at both ends; length L = \frac{\lambda}{2} so \lambda = 2L.
Second harmonic of a string fixed at both endsTwo antinodes and three nodes; length L = \lambda so \lambda = L.
Third harmonic of a string fixed at both endsThree antinodes and four nodes; length L = \frac{3\lambda}{2} so \lambda = \frac{2L}{3}.
How to calculate harmonic frequencies on a stringf_n = n \times f_1 where n = 1, 2, 3,\ldots and f_1 = \frac{v}{2L}.
Speed of wave on a string formulav = \sqrt{\frac{T}{\mu}} where T is tension and \mu is mass per unit length.
Effect of increasing tension on stationary wave frequencyFrequency increases because wave speed increases (v = \sqrt{T/\mu}) while wavelength remains fixed by boundaries.
Effect of increasing string density on stationary wave frequencyFrequency decreases because wave speed decreases (v = \sqrt{T/\mu}) for fixed tension.
Open air column stationary wave (both ends open)Antinodes at both open ends, node(s) in between; fundamental: \lambda = 2L.
Closed air column stationary wave (one end closed)Node at closed end, antinode at open end; fundamental: \lambda = 4L.
Overtones of a closed air columnOnly odd harmonics: f_n = n f_1 where n = 1, 3, 5,\ldots; fundamental \lambda = 4L.
How to find node positions in a stationary waveNodes occur where the path difference between incident and reflected waves is an odd multiple of \frac{\lambda}{2}.
Energy in a stationary waveTotal energy is constant but oscillates periodically between kinetic energy (at antinodes) and potential energy (near nodes).