Snell’s law
If we have two objects with ‘absolute’ refractive indexes of
Where:
n_1 is the refractive index of the first material.n_2 is the refractive index of the second material.\theta_1 is the angle at which light enters the boundary\theta_2 is the angle at which light leaves the boundary
Assuming we know 3 out of the 4 unknowns, we can find any of them. We can re-arrange the formula above into any of:
n_1=\frac{n_2\sin\theta_2}{\sin\theta_1} n_2=\frac{n_1\sin\theta_1}{\sin\theta_2} \theta_1=\sin^{-1}(\frac{n_2\sin\theta_2}{n_1}) \theta_2=\sin^{-1}(\frac{n_1\sin\theta_1}{n_2})
This is Snell’s law!
What is each material?
- The first material is the material the light starts in.
- The second material is the material the light goes into.
flashcards
| Question | Answer |
|---|---|
| Snell’s Law formula | |
| Refractive index of the first material (the material light starts in) | |
| Refractive index of the second material (the material light goes into) | |
| Angle at which light enters the boundary | |
| Angle at which light leaves the boundary | |
| Formula for | |
| Formula for | |
| Formula for | |
| Formula for | |
| In Snell’s law, what is the first material? | The material the light starts in |
| In Snell’s law, what is the second material? | The material the light goes into |