Snell’s law

If we have two objects with ‘absolute’ refractive indexes of n_1 and n_2, we can say that:

n_1\sin\theta_1=n_2\sin\theta_1

Where:

Assuming we know 3 out of the 4 unknowns, we can find any of them. We can re-arrange the formula above into any of:

This is Snell’s law!

What is each material?

flashcards

QuestionAnswer
Snell’s Law formulan_1\sin\theta_1 = n_2\sin\theta_2
n_1 represents in Snell’s lawRefractive index of the first material (the material light starts in)
n_2 represents in Snell’s lawRefractive index of the second material (the material light goes into)
\theta_1 represents in Snell’s lawAngle at which light enters the boundary
\theta_2 represents in Snell’s lawAngle at which light leaves the boundary
Formula for n_1 when rearranged from Snell’s lawn_1 = \frac{n_2 \sin\theta_2}{\sin\theta_1}
Formula for n_2 when rearranged from Snell’s lawn_2 = \frac{n_1 \sin\theta_1}{\sin\theta_2}
Formula for \theta_1 when rearranged from Snell’s law\theta_1 = \sin^{-1}\left(\frac{n_2 \sin\theta_2}{n_1}\right)
Formula for \theta_2 when rearranged from Snell’s law\theta_2 = \sin^{-1}\left(\frac{n_1 \sin\theta_1}{n_2}\right)
In Snell’s law, what is the first material?The material the light starts in
In Snell’s law, what is the second material?The material the light goes into