Separating vectors into components

While sometimes it is useful to know just the magnitude and direction of a vector, other times (particularly when we’re doing calculations) it’s much more useful to know the horizontal and vertical components of a vector.

What are components?

Theyr’e just the horizontal and vertical parts of a vector.

So instead of describing a vector as “5m at 30 degrees to the horizontal”, we can describe it as “4.33m horizontally and 2.5m vertically”.

How to find the components of a vector

To find the components of a vector, we can just use some trigonometry.

For this vector:

        ^               +
        |             /               
        |           /                 
        |         /  F                
  Fcosθ |       /                     
        |     /                       
        |   /                         
        | /   θ                        
        + -------------->             
              Fcosθ    

For the vector indicated by the diagonal arrow with magnitude F:

So if we know the magnitude of the vector and the angle it makes with the horizontal, we can easily find its components using these formulas.

Find the horizontal and vertical components of the vector 9m at 30^\circ to the horizontal.

Uses of components of vectors

We need to split up vectors into their components whenever we do any calculations regarding motion.

flashcards

QuestionAnswer
What are the two parts vectors are separated into for calculations?Horizontal and vertical components.
Instead of saying “5m at 30° to the horizontal”, how could the vector be described using components?“4.33m horizontally and 2.5m vertically”.
What trigonometric function is used to find the horizontal component of a vector?F \cos \theta, where F is the magnitude and \theta is the angle to the horizontal.
What trigonometric function is used to find the vertical component of a vector?F \sin \theta, where F is the magnitude and \theta is the angle to the horizontal.
The vector 9m at 30^\circ to the horizontal: what is its horizontal component?9 \cos 30^\circ = 9 \times 0.866 = 7.794m
The vector 9m at 30^\circ to the horizontal: what is its vertical component?9 \sin 30^\circ = 9 \times 0.5 = 4.5m
When is it necessary to split vectors into components?Whenever doing any calculations regarding motion.