Rationalising the denominator

Rationalising the denominator

When we have a surd in the denominator of a fraction, we can rationalise the denominator by multiplying both the numerator and denominator by the surd (or the negated factor).

Example: rationalise \frac{1}{\sqrt{2}}

Example: rationalise \frac{3}{\sqrt{5}}

Example: rationalise \frac{4}{\sqrt{3}}

Example: rationalise \frac{\sqrt{2}}{1+\sqrt{3}}

Example: rationalise \frac{5}{2+\sqrt{7}}

Example: rationalise \frac{3\sqrt{5}}{4-\sqrt{2}}

flashcards

QuestionAnswer
What is the process of rationalising the denominator when it contains a single surd?Multiply the numerator and denominator by the surd in the denominator.
How do you rationalise \frac{1}{\sqrt{2}}?\frac{1\times\sqrt{2}}{\sqrt{2}\times\sqrt{2}} = \frac{\sqrt{2}}{2}
How do you rationalise \frac{3}{\sqrt{5}}?\frac{3\times\sqrt{5}}{\sqrt{5}\times\sqrt{5}} = \frac{3\sqrt{5}}{5}
How do you rationalise \frac{4}{\sqrt{3}}?\frac{4\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}} = \frac{4\sqrt{3}}{3}
How do you rationalise \frac{\sqrt{2}}{1+\sqrt{3}}?Multiply by the conjugate: \frac{\sqrt{2}(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})} = \frac{\sqrt{2}-\sqrt{6}}{1-3} = \frac{\sqrt{2}-\sqrt{6}}{-2}
How do you rationalise \frac{5}{2+\sqrt{7}}?Multiply by the conjugate: \frac{5(2-\sqrt{7})}{(2+\sqrt{7})(2-\sqrt{7})} = \frac{10-5\sqrt{7}}{4-7} = \frac{10-5\sqrt{7}}{-3}
How do you rationalise \frac{3\sqrt{5}}{4-\sqrt{2}}?Multiply by the conjugate: \frac{3\sqrt{5}(4+\sqrt{2})}{(4-\sqrt{2})(4+\sqrt{2})} = \frac{12\sqrt{5}+3\sqrt{10}}{16-2} = \frac{12\sqrt{5}+3\sqrt{10}}{14}