Photoelectric equation

When working with the photoelectric effect, we can link together:

Linking them all together is the photoelectric equation!

E_\text{photon}=\phi+E_\text{kmax}

Where:

Calculating from frequency

If we don’t have the photon energy but instead have the frequency of the incident light, we can calculate the energy of the photon using the equation:

E_\text{photon} = hf

And then just substitute that into the photoelectric equation. In one single equation, we can replace E_\text{photon} with hf to get:

hf = \phi + E_\text{kmax}

Calculating from wavelength

To calculate from the wavelength, we need to use three equations…

In one single equation, we get:

\frac{hc}{\lambda} = \phi + E_\text{kmax}

c is the speed of light: 3.00\times10^8ms^{-1}.

flashcards

QuestionAnswer
E=M_{photon} formula linking photon energy, work function, and kinetic energyE_{\text{photon}} = \phi + E_{\text{kmax}} where E_{\text{photon}} is incident photon energy, \phi is work function, and E_{\text{kmax}} is maximum kinetic energy of emitted electrons
What does E_{\text{kmax}} represent in the photoelectric equation?It is the maximum kinetic energy of the emitted electrons; electrons may have less but cannot have more
How do you calculate photon energy from frequency?E_{\text{photon}} = hf, where h is Planck’s constant and f is frequency
What is the photoelectric equation using frequency?hf = \phi + E_{\text{kmax}}
How do you calculate the frequency of EM radiation from wavelength?f = \frac{3.00 \times 10^8}{\lambda}, where wavelength \lambda is in meters and 3.00 \times 10^8 \text{ m/s} is the speed of light
What is the photoelectric equation using wavelength?\frac{hc}{\lambda} = \phi + E_{\text{kmax}}, where c is the speed of light (3.00 \times 10^8 \text{ m/s})
What are the three steps to find the photoelectric equation from wavelength?1. Convert wavelength to frequency: f = \frac{c}{\lambda}
2. Calculate photon energy: E_{\text{photon}} = hf
3. Substitute into photoelectric equation: hf = \phi + E_{\text{kmax}}