Logarithm function gradient

Gradient of y=\ln x

\frac{dy}{dx} \ln x = \frac{1}{x}

So the gradient of y=\log{ax} is \frac{1}{x} as well.

Find the derivative:
- y=k\ln x
- \frac{dy}{dx} k\ln x = k \frac{1}{x} = \frac{k}{x}

So the gradient of y=k\ln x is \frac{k}{x}.

Question	Answer
What is the gradient of y = \ln x?	\frac{dy}{dx} \ln x = \frac{1}{x}
How do you rewrite y = \log{ax} before differentiating?	y = \log a + \log x
What is the derivative of a constant like \log a?	0
What is the gradient of y = \log{ax}?	\frac{1}{x}
What is the gradient of y = k\ln x?	\frac{k}{x}