De Broglie wavelength

Now we know that a particle can also, in cases, be represented as a wave, that means we can find the wavelength of a particle!

There’s isn’t a proven way of calculating it, but de Broglie theorised that:

\lambda=\frac h{mv}

\lambda is the wavelength of the particle
h is the planck constant, 6.63\times10^{-34}\,Js
mv is the momentum of the particle:
- m is its mass
- v is its velocity
- we multiply them together to get momentum.

flashcards

Question	Answer
Who proposed the equation \lambda = h/(mv)?	Louis de Broglie.
What does the variable \lambda represent in the de Broglie equation?	The wavelength of the particle.
What is the value of the Planck constant h?	6.63\times10^{-34}\,Js.
How is momentum represented in the de Broglie wavelength formula \lambda = h/(mv)?	It is represented by mv (mass \times velocity).
What two properties of a particle are multiplied to find its momentum in the de Broglie equation?	Mass (m) and velocity (v).
A particle can be represented as a wave; what property of the wave can be calculated?	The wavelength.

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momentum planck constant wavelength flashcards mass velocity