\cosh, or hyperbolic cosine, is defined like this:
\cosh x=\frac{e^x+e^{-x}}2
It’s pronounced ‘cosh’ - as it’s spelt.
Using the definition for \tanh:
\tanh=\frac{\sinh}{\cosh}
…we can deduce that:
\cosh=\frac{\sinh}{\tanh}