Converting exponentials into logarithms

We know how to solve and manipulate logarithms (see laws of logarithms), but what if we have an exponential expression that we want to convert into a logarithmic one?

We can just use the definition of logarithms to rewrite the exponential expression a^x=b as a logarithmic expression x=\log_a(b).

Convert 2^3=8 into a logarithmic expression

Convert 5^x=25 into a logarithmic expression

Solve for x: 3^x=27

Solve for x: 10^{x-1}=1000

Find the exact value of x: e^{2x}=7

Find the exact value of x: 4^{x+1}=16

Solve for x: (2^x)^3=64

Solve for x: (5^{2x-1})^2=125

flashcards

QuestionAnswer
How do you convert the exponential a^x=b into a logarithmic expression?x = \log_a(b)
Convert 2^3=8 into a logarithmic expression.\log_2(8)
Convert 5^x=25 into a logarithmic expression and solve for x.x = \log_5(25) ; x=2
Solve for x: 3^x=27x = \log_3(27) ; x=3
Solve for x: 10^{x-1}=1000x-1 = \log_{10}(1000) ; x-1=3 ; x=4
Find the exact value of x: e^{2x}=72x = \ln(7) ; x = \frac{\ln(7)}{2}
Find the exact value of x: 4^{x+1}=16x+1 = \log_4(16) ; x+1=2 ; x=1
Solve for x: (2^x)^3=643x = \log_2(64) ; 3x=6 ; x=2
Solve for x: (5^{2x-1})^2=1255^{4x-2}=125 ; 4x-2 = \log_5(125) ; 4x-2=3 ; 4x=5 ; x=\frac{5}{4}