Cartesian to polar coordinates

If we have a Cartesian coordinate in the form (x,y), then we can convert these to a polar coordinate, using our [[ /polar coordinate identities|polar coordinate identities]] from before!

General steps

polar coordinates are in the form (r,\theta), where:

To find the magnitude of the polar coordinate, r:

Then to find the angle, \theta:

Note: If the x coordinate is negative, we need to add \pi to our answer for \theta. That’s because, otherwise, the angle we got from \tan^{-1}(\frac yx) would be in the wrong quadrant.

Find the polar coordinate from the Cartesian (4,4)

Convert the cartesian coordinate (-1,4) to polar coordinates (to 3sf)

Convert the cartesian coordinate (-1,-4) to polar coordinates (to 3sf)

Convert the cartesian coordinate (1,-4) to polar coordinates (to 3sf)

Write (4,8) as a set of polar coordinates

flashcards

QuestionAnswer
What is the formula for r (magnitude) when converting Cartesian (x,y) to polar coordinates?r=\sqrt{x^2+y^2}
What is the formula for \theta (angle) when converting Cartesian (x,y) to polar coordinates?\theta=\tan^{-1}(\frac yx)
What must you do to \theta if the x coordinate is negative when converting to polar coordinates?We need to add \pi to our answer for \theta.
Why must you add \pi to \theta when x is negative?Because otherwise the angle from \tan^{-1}(\frac yx) would be in the wrong quadrant.
Convert the Cartesian coordinate (4,4) to polar coordinates.(4\sqrt2, \frac{\pi}4)
Convert the Cartesian coordinate (-1,4) to polar coordinates (to 3sf).(4.123, 1.816)
Convert the Cartesian coordinate (-1,-4) to polar coordinates (to 3sf).(4.123, 1.816)
Convert the Cartesian coordinate (1,-4) to polar coordinates (to 3sf).(4.123, -1.326)
Convert the Cartesian coordinate (4,8) to polar coordinates.(4\sqrt5, 1.107)
What is the polar coordinate r a measure of?The magnitude, the distance of a point from the origin.
What is the polar coordinate \theta a measure of?The bearing from the origin, starting from the right-stretching line and going anticlockwise.
What do you need to do if x is positive and y is negative when finding \theta?Do not add \pi to the \tan^{-1}(\frac yx) result.