Calculating tangent
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In other words:
…where
Calculate \tan(45^\degree) .
\tan(45^\degree) = \frac{\sin(45^\degree)}{\cos(45^\degree)} \sin(45^\degree) = \frac{\sqrt{2}}{2} \cos(45^\degree) = \frac{\sqrt{2}}{2} \tan(45^\degree) = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} \tan(45^\degree) = 1 - Answer:
\tan(45^\degree) = 1 .
Calculate \tan(60^\degree) .
\tan(60^\degree) = \frac{\sin(60^\degree)}{\cos(60^\degree)} \sin(60^\degree) = \frac{\sqrt{3}}{2} \cos(60^\degree) = \frac{1}{2} \tan(60^\degree) = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} \tan(60^\degree) = \frac{\sqrt{3}}{1} \tan(60^\degree) = \sqrt{3} - Answer:
\tan(60^\degree) = \sqrt{3} .
Calculate \tan(30^\degree) .
\tan(30^\degree) = \frac{\sin(30^\degree)}{\cos(30^\degree)} \sin(30^\degree) = \frac{1}{2} \cos(30^\degree) = \frac{\sqrt{3}}{2} \tan(30^\degree) = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} \tan(30^\degree) = \\frac{1}{\sqrt{3}} - Answer:
\tan(30^\degree) = \frac{1}{\sqrt{3}} .
flashcards
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| How is the tangent function defined? | |
| What is | |
| Calculate | |
| What is | |
| Calculate | |
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