Base e exponentials
There’s a special case of exponential functions, where we use a base of e.
You can find more about e in the euler’s number topic. It’s
a number with some special properties, and it’s about 2.71828.
Reciprocal exponentials
If, instead of y=e^x, we have y=e^{-x}, we can rewrite it as
y=\frac{1}{e^x}.
That’s a decay graph, as the base is less than 1 (because
\frac{1}{e} is less than 1).
Gradient of e^x
The gradient of e^x is exactly the same as the y value at that point.
\frac{d}{dx}e^x = e^x
For example, at the point (0, 1), the gradient is 1 (because e^0=1). At
the point
Gradient of e^{kx}
e^{kx} doesn’t exactly differentiate to
e^{kx}, but it does differentiate to a constant multiple of e^{kx}:
ke^{kx}.
\frac{d}{dx}e^{kx} = ke^{kx}
Gradient of e^{-x}
The gradient of e^{-x} is -e^{-x} - it’s the same as the rule for e^{kx},
but with a negative constant instead of a positive one.
\frac{d}{dx}e^{-x} = -e^{-x}
Gradient of e^{-kx}
This is basically just saying that k is a negative constant, so the gradient
of e^{-kx} is -ke^{-kx} - it follows the same rule as e^{kx}, but with a
negative constant instead of a positive one.
\frac{d}{dx}e^{-kx} = -ke^{-kx}
Gradient of e^{f(x)}
The gradient of e^{f(x)} is f'(x)e^{f(x)} - it’s the same as the rule for
e^{kx}, but instead of k being a constant, it’s f'(x), which is the
derivative of f(x).
\frac{d}{dx}e^{f(x)} = f'(x)e^{f(x)}
| Question | Answer |
| What is the approximate value of Euler’s number e? | e \approx 2.71828 |
| How can y=e^{-x} be rewritten? | y=\frac{1}{e^x} |
| Why is y=e^{-x} considered a decay graph? | The base \frac{1}{e} is less than 1. |
| What is the derivative of e^x? | \frac{d}{dx}e^x = e^x |
| What is the gradient of e^x at the point (0, 1)? | The gradient is 1 (because e^0=1). |
| What is the derivative of e^{kx}? | \frac{d}{dx}e^{kx} = ke^{kx} |
| What is the derivative of e^{-x}? | \frac{d}{dx}e^{-x} = -e^{-x} |
| What is the derivative of e^{-kx}? | \frac{d}{dx}e^{-kx} = -ke^{-kx} |
| What is the derivative of e^{f(x)}? | \frac{d}{dx}e^{f(x)} = f'(x)e^{f(x)} |