Adding vector quantities

If we have two vector quantities, we can add them to get a new vector quantity.

The thing we get after adding two vectors together is called the resultant, or more specifically, resultant vector.

Adding vectors of the same direction

Suppose we have two vectors, \vec A and \vec B, which are in the same direction. We can add them together by adding their magnitudes together.

For example, if \vec A has a magnitude of 3m and \vec B has a magnitude of 5m, then the resultant vector \vec R will have a magnitude of 3m+5m=8m.

That’s because, if you suppose the vector represents a movement, then we will have moved 3m in the direction of \vec A, and then 5m in the same direction, so we will have moved a total of 8m in that direction.

A car moves 30km north, then 20km north. What is the resultant vector for the car’s movement?

Adding vectors of opposite directions

If we have two vectors, \vec A and \vec B, which are in opposite directions, then we can add them together by subtracting the smaller magnitude from the larger magnitude, and keeping the direction of the larger vector.

A car moves 30km north, then 20km south. What is the resultant vector for the car’s movement?

A person cycles 10km east, then 15km west. What is the resultant vector for the person’s movement?

Bearings

We can write the direction of a vector as a bearing, which is the angle that the vector makes with the north direction, measured clockwise.

For example, if a vector has a bearing of 90\degree, then it is pointing east, because it is 90\degree clockwise from north.

Adding vectors at right angles

We can also find the resultant of two vectors if they’re at right angles to each other.

We can use:

Boat A is 6km east of a lighthouse, and boat B is 8km north of the lighthouse. What is the resultant position vector OF B FROM A?

Draw a right triangle with the lighthouse at the right angle, boat A at one end of the hypotenuse, and boat B at the other end of the hypotenuse:

        B
          +
          | \
          |   \
          |     \
          |       \
     8km  |         \
          |           \
          |             \
          |            θ  \
          + --------------- +
        L         6km         A

flashcards

QuestionAnswer
What is the name for the vector obtained after adding two vectors together?The resultant, or more specifically, the resultant vector.
How do you add two vectors that are in the same direction?Add their magnitudes together; the resultant vector has that magnitude in the same direction.
If \vec A = 3m east and \vec B = 5m east, what is the resultant \vec R?\vec R has a magnitude of 3m + 5m = 8m, direction east.
A car moves 30km north, then 20km north. What is the resultant vector?50km north
How do you add two vectors that are in opposite directions?Subtract the smaller magnitude from the larger magnitude; the resultant keeps the direction of the larger vector.
If $\vec A
A car moves 30km north, then 20km south. What is the resultant vector?10km north
A person cycles 10km east, then 15km west. What is the resultant vector?5km west
Define a bearing as a direction for a vector.The angle the vector makes with the north direction, measured clockwise.
What is the bearing of a vector pointing directly east?90\degree
What mathematical tools are used to add two vectors at right angles?Pythagorean theorem for magnitude; trigonometry for direction.
Boat A is 6km east of a lighthouse, boat B is 8km north. Find the position vector of B from A.Magnitude = \sqrt{6^2 + 8^2} = 10km; angle \theta = \tan^{-1}(8/6) \approx 53.13\degree east of north; bearing = 360\degree - 53.13\degree = 306.87\degree. (Note: the document example gave 323.13\degree from a different reference, question expects calculation based on triangle position)
In the triangle for the boats (B from A), what formula gives the magnitude of the resultant?Pythagorean theorem: a^2 + b^2 = c^2, where a=6km, b=8km, so c = \sqrt{36+64} = 10km.
How is the angle \theta found in the boat example?\tan\theta = \frac{8}{6}, so \theta = \tan^{-1}(8/6).
How is the bearing of the resultant vector calculated from the east-west line in the boat example?Add 270\degree to the angle \theta measured from east (or subtract from 360\degree depending on reference; document says add 270\degree to get 323.13\degree).