Acceleration
Acceleration is the rate of change of velocity.
It’s basically how quickly something speeds up.
Because it’s the rate of change of velocity, it’s a vector quantity.
\text{acceleration}=\text{velocity}\div\text{time}
Calculations
The velocity of a car increases from 10ms^{-1} to 30ms^{-1} in 4s. Calculate its acceleration.
- In this case we need to use the change in velocity,
\Delta v . \Delta v=30-10=20 a=\frac{\Delta v}t a=\frac{20}4=5 - Answer:
5ms^{-1}
A car accelerates at 2ms^{-2} for 5s. Calculate the change in velocity.
a=\frac{\Delta v}t \Delta v=at \Delta v=2\times5=10 - Answer:
10ms^{-1}
A bike accelerates at 0.5ms^{-2} for 10s. Calculate the change in velocity.
a=\frac{\Delta v}t \Delta v=at \Delta v=0.5\times10=5 - Answer:
5ms^{-1}
A car accelerates at 3ms^{-2} until reaching a velocity of 20ms^{-1} . Calculate the time taken to reach this velocity.
a=\frac vt t=\frac v a t=\frac{20}3\approx6.67 - Answer:
6.67s
A van accelerates at 4ms^{-2} for 8s. Calculate the change in velocity.
a=\frac{\Delta v}t \Delta v=at \Delta v=4\times8=32 - Answer:
32ms^{-1}
A truck accelerates at 5ms^{-2} for 6s. Calculate the change in velocity.
a=\frac{\Delta v}t \Delta v=at \Delta v=5\times6=30 - Answer:
30ms^{-1}
A car accelerates at 1ms^{-2} until reaching a velocity of 15ms^{-1} . Calculate the time taken to reach this velocity.
a=\frac vt t=\frac v a t=\frac{15}1=15 - Answer:
15s
A bike accelerates at 0.2ms^{-2} for 12s. Calculate the change in velocity.
a=\frac{\Delta v}t \Delta v=at \Delta v=0.2\times12=2.4 - Answer:
2.4ms^{-1}